6. sin150 Sin(90+60)​=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90..

6. sin150 Sin(90+60)​=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2​ cos(90+60)=−sin60∘=−8​/2cos(180∘−30)=−cos30=−3​/2​ cos150
Video solution 1: 6. sin150 Sin(90+60)​=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2​ cos(90+60)=−sin60∘=−8​/2cos(180∘−30)=−cos30=−3​/2​ cos150
Video solution 2: 6. sin150 Sin(90+60)​=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2​ cos(90+60)=−sin60∘=−8​/2cos(180∘−30)=−cos30=−3​/2​ cos150

Show that : (i) (1-sin60^(@))/(cos60^(@))=(tan60^(@)-1)/(tan60^(@)+1

Evaluate: sin 60° cos30° + sin 30° cos 60°

If sin 600° cos 30° + cos 120° sin 150° = k, then k = (a) 0 (b) 1 (c) −1 (d) None of these

What is the value of sin150? - Quora

⏩SOLVED:Evaluate the following: (i) sin60^∘ cos30^∘+sin30^∘ cos60^∘…

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What is the value of sin150? - Quora

If sin 600° cos 30° + cos 120° sin 150° = k, then k = (a) 0 (b) 1 (c) −1 (d) None of these

Oblicz a) (sin45+ctg45) (6 sin60- ctg30) = b) sin120·cos150+tg²135= c) 5 cos (-390)·sin (-660)·tg315= d)

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