At 300 K, 36 g of glucose present per litre in its solution has an osm

pi=CRT" (C = molar concentration)" (pi(1))/(pi(2))=(C(1))/(C(2))," "(4.98)/(1.52)=(36//180)/(C(2))" or "C(2)=(36)/(180)xx(1.52)/(4.98)="0.061 M"

⏩SOLVED:At 300 K, 36 g of glucose present per litre in its…

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At 300 K, 36 g of glucose present per litre in its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bar the same